X^2+2x+1-4=5

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Solution for X^2+2x+1-4=5 equation: 


Simplifying
X2 + 2x + 1 + -4 = 5

Reorder the terms:
1 + -4 + X2 + 2x = 5

Combine like terms: 1 + -4 = -3
-3 + X2 + 2x = 5

Solving
-3 + X2 + 2x = 5

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + X2 + 3 + 2x = 5 + 3

Reorder the terms:
-3 + 3 + X2 + 2x = 5 + 3

Combine like terms: -3 + 3 = 0
0 + X2 + 2x = 5 + 3
X2 + 2x = 5 + 3

Combine like terms: 5 + 3 = 8
X2 + 2x = 8

Add '-2x' to each side of the equation.
X2 + 2x + -2x = 8 + -2x

Combine like terms: 2x + -2x = 0
X2 + 0 = 8 + -2x
X2 = 8 + -2x

Simplifying
X2 = 8 + -2x

Reorder the terms:
-8 + X2 + 2x = 8 + -2x + -8 + 2x

Reorder the terms:
-8 + X2 + 2x = 8 + -8 + -2x + 2x

Combine like terms: 8 + -8 = 0
-8 + X2 + 2x = 0 + -2x + 2x
-8 + X2 + 2x = -2x + 2x

Combine like terms: -2x + 2x = 0
-8 + X2 + 2x = 0

The solution to this equation could not be determined.

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